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ROUTE (642-902): Distribute List Questions
Question 1
Refer to the exhibit. R1 and R2 belong to the RIP routing domain that includes the networks 10.20.0.0/16 and 10.21.0.0/16. R3 and R4 are performing two-way route redistribution between OSPF and RIP. A network administrator has discovered that R2 is receiving OSPF routes for the networks 10.20.0.0/16 and 10.21.0.0/16 and a routing loop has occurred.
Which action will correct this problem?
A. Apply an inbound ACL to the R2 serial interface.
B. Change the RIP administrative distance on R3 to 110.
C. Configure distribute-lists on R3 and R4.
D. Set the OSPF default metric to 20.
E. Change the OSPF administrative distance on R3 to 110.
Answer: C
Question 2
Refer to the exhibit. Which one statement is true?
A. Traffic from the 172.16.0.0/16 network will be blocked by the ACL.
B. The 10.0.0.0/8 network will not be advertised by Router B because the network statement for the 10.0.0.0/8 network is missing from Router
C. The 10.0.0.0/8 network will not be in the routing table on Router B.
D. Users on the 10.0.0.0/8 network can successfully ping users on the 192.168.5.0/24 network, but users on the 192.168.5.0/24 cannot successfully ping users on the 10.0.0.0/8 network.
E. Router B will not advertise the 10.0.0.0/8 network because it is blocked by the ACL.
Answer: E
Question 3
Based on the information in the exhibit, which statement is true?
A. RTC will be able to access the 10.0.0.0 network.
B. RTC will not have the 10.0.0.0 network in its routing table.
C. RTC will not have the 192.168.10.0 network in its routing table.
D. RTB will not have the 10.0.0.0 network in its routing table.
E. RTB and RTC will not have the 10.0.0.0 network in their routing tables.
Answer: B
Explanation
The distribute list only permits network 192.168.10.0/24 to be sent out of interface S0/0 so RTC only receives advertisement of this network -> 10.0.0.0 network will not exist in the routing table of RTC.
Question 4
Study this exhibit below carefully. What is the effect of the distribute-list command in the R1 configuration?
A – R1 will permit only the 10.0.0.0/24 route in the R2 RIP updates
B – R1 will not filter any routes because there is no exact prefix match
C – R1 will filter the 10.1.0.0/24 and the 172.24.1.0/24 routes from the R2 RIP updates
D – R1 will filter only the 172.24.1.0/24 route from the ***-R2 RIP updates
Answer: C
Explanation
The command “distribute-list 10 in Serial0″ will create an incoming distribute list for interface serial 0 and refers to access list 10. So it will permit routing updates from 10.0.x.x network while other entries (in this case the 10.1.0.0/24 and 172.24.1.0/24 networks) will be filtered out from the routing update received on interface S0.
Question 5
Router RTA is configured as follows:
RTA (config)#router rip
RTA(config-router)#network 10.0.0.0
RTA(config-router)#distribute-list 44 in interface BRIO
RTA(config-router)#exit
RTA(config)#access-list 44 deny 172.16.1.0 0.0.0.255
RTA(config)#access-list 44 permit any
What are the effects of this RIP configuration on router RTA? (Choose two)
A – no routing updates will be sent from router RTA on interface BRIO to router RTX
B – router RTA will not advertise the 10.0.0.0 network to router RTX
C – the route to network 172.16.1.0 will not be entered into the routing table on router RTA
D – user traffic from the 172.16.1.0 network is denied by access-list 44
E – the routing table on router RTA will be updated with the route to router RTW
Answer: C E
Explanation
Distribute list are used to filter routing updates and they are based on access lists. In this case, an access list of 44 was created to deny the route from network 172.16.1.0/24 so this route will not be entered into the routing table of RTA. But the route from RTW can be entered because it is not filtered by the access list
A and B are not correct because the distribute list is applied to the inbound direction of interface BRI0 so outgoing routing updated will not be filtered.
D is not correct because distribute list just filters routing updates so user traffic from network 172.16.1.0 will not be denied.
Refer to the exhibit. R1 and R2 belong to the RIP routing domain that includes the networks 10.20.0.0/16 and 10.21.0.0/16. R3 and R4 are performing two-way route redistribution between OSPF and RIP. A network administrator has discovered that R2 is receiving OSPF routes for the networks 10.20.0.0/16 and 10.21.0.0/16 and a routing loop has occurred.
Which action will correct this problem?
A. Apply an inbound ACL to the R2 serial interface.
B. Change the RIP administrative distance on R3 to 110.
C. Configure distribute-lists on R3 and R4.
D. Set the OSPF default metric to 20.
E. Change the OSPF administrative distance on R3 to 110.
Answer: C
Question 2
Refer to the exhibit. Which one statement is true?
A. Traffic from the 172.16.0.0/16 network will be blocked by the ACL.
B. The 10.0.0.0/8 network will not be advertised by Router B because the network statement for the 10.0.0.0/8 network is missing from Router
C. The 10.0.0.0/8 network will not be in the routing table on Router B.
D. Users on the 10.0.0.0/8 network can successfully ping users on the 192.168.5.0/24 network, but users on the 192.168.5.0/24 cannot successfully ping users on the 10.0.0.0/8 network.
E. Router B will not advertise the 10.0.0.0/8 network because it is blocked by the ACL.
Answer: E
Question 3
Based on the information in the exhibit, which statement is true?
B. RTC will not have the 10.0.0.0 network in its routing table.
C. RTC will not have the 192.168.10.0 network in its routing table.
D. RTB will not have the 10.0.0.0 network in its routing table.
E. RTB and RTC will not have the 10.0.0.0 network in their routing tables.
Answer: B
Explanation
The distribute list only permits network 192.168.10.0/24 to be sent out of interface S0/0 so RTC only receives advertisement of this network -> 10.0.0.0 network will not exist in the routing table of RTC.
Question 4
Study this exhibit below carefully. What is the effect of the distribute-list command in the R1 configuration?
B – R1 will not filter any routes because there is no exact prefix match
C – R1 will filter the 10.1.0.0/24 and the 172.24.1.0/24 routes from the R2 RIP updates
D – R1 will filter only the 172.24.1.0/24 route from the ***-R2 RIP updates
Answer: C
Explanation
The command “distribute-list 10 in Serial0″ will create an incoming distribute list for interface serial 0 and refers to access list 10. So it will permit routing updates from 10.0.x.x network while other entries (in this case the 10.1.0.0/24 and 172.24.1.0/24 networks) will be filtered out from the routing update received on interface S0.
Question 5
Router RTA is configured as follows:
RTA (config)#router rip
RTA(config-router)#network 10.0.0.0
RTA(config-router)#distribute-list 44 in interface BRIO
RTA(config-router)#exit
RTA(config)#access-list 44 deny 172.16.1.0 0.0.0.255
RTA(config)#access-list 44 permit any
A – no routing updates will be sent from router RTA on interface BRIO to router RTX
B – router RTA will not advertise the 10.0.0.0 network to router RTX
C – the route to network 172.16.1.0 will not be entered into the routing table on router RTA
D – user traffic from the 172.16.1.0 network is denied by access-list 44
E – the routing table on router RTA will be updated with the route to router RTW
Answer: C E
Explanation
Distribute list are used to filter routing updates and they are based on access lists. In this case, an access list of 44 was created to deny the route from network 172.16.1.0/24 so this route will not be entered into the routing table of RTA. But the route from RTW can be entered because it is not filtered by the access list
A and B are not correct because the distribute list is applied to the inbound direction of interface BRI0 so outgoing routing updated will not be filtered.
D is not correct because distribute list just filters routing updates so user traffic from network 172.16.1.0 will not be denied.